Question

Find the y-coordinate of the vertex and
the axis of symmetry for f(x)=8x-2x^2

Answer 1

well thew axis of symmetry for a parabola

\[y = ax^2 + bx + c\]

is

\[x = \frac{-b}{2a}\]

in your question b = 8 and a = -2

substitute these into the equation to find the line of symmetry.

to find the vertex, substitute the value of x from the line of symmetry into the original equation.

The vertex lies on the line of symmetry.

hope this helps.