quotient function (x^3 + x / x^2 - 1) and I need to find the derivative and stationery points.

here is the derivative:
(3x^2+1)(x^2-1) - 2x^2(x^2+1) (top line)
/ (x^2-1)^2

Now I need to solve for x but I am stuck.... please help!

Question

quotient function (x^3 + x / x^2 - 1) and I need to find the derivative and stationery points.

here is the derivative: 
(3x^2+1)(x^2-1) - 2x^2(x^2+1) (top line)
/ (x^2-1)^2

Now I need to solve for x but I am stuck.... please help!

anonymous · Answer

Do you mean (x^3 + x)/(x^2 - 1) or (x^3 + x/x^2 -1)?

ranga · Answer

top line last after the minus sign should be: 2x(x^3 + x)

ranga · Answer

$$f(x) = \frac{ x^3+x }{ x^2-1 }$$$$f'(x) = \frac{ (3x^2+1)(x^2-1) - 2x(x^3+x) }{ (x^2-1)^2 } = 0$$