Question

X^2+4x

x^2=-3x-4

x^2-2x+7=7+x

Answer 1

can anyone show me how to solve these quadratics

Answer 2

not pre-algebra sorry

Answer 3

What is the first one?

The second equation can be solved by following:

\[x^2 + 3x + 4 = 0\]
\[\Delta = 3^2 - 4*4 = -7 < 0 \rightarrow \] No solution (or imaginary solution)

The third one is:
\[x^2 - 3x = 0\] then \[x_1 = 0\] or \[x_2 = 3\]

That's all