What are all the real zeroes y = (x –12)3 – 7 ?

i found this solution
0=(x−12)3−7

7=(x−12)3−7+7

7=(x−12)3

7√3=(x−12)3−−−−−−−−√3

7√3=x−12−7√3+12=x−12+12−−x=12+7√3

BUT WHAT DO THOSE ARROWS MEAN?
can someone explain this to me? How they got from step to step?

Question

What are all the real zeroes y = (x –12)3 – 7  ?

i found this solution
0=(x−12)3−7

7=(x−12)3−7+7

7=(x−12)3

7√3=(x−12)3−−−−−−−−√3

7√3=x−12−>7√3+12=x−12+12−−>x=12+7√3

BUT WHAT DO THOSE ARROWS MEAN?
can someone explain this to me? How they got from step to step?

anonymous · Answer

i was looking at this http://openstudy.com/study#/updates/50c8f830e4b0a14e4368e234 but i don't get how they got to that last, final part of it, and still don't get the zeroes

solomonzelman · Answer

$$y = (x –12)^3 – 7$$this?