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0=(3)(a^2)(b)(a+b) where a= 2^x - 4 and b= 4^x - 2 What is the sum of all real numbers x that satisfy
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3 possiblities a^2=0 , b=0 , or a+b=0
if a^2=0 a=0 so 2^x=4 x=2
if b=0 4^x=2 x=1/2
ifa+b=0 4^x+2^x-6=0 let 2^x=c then c^2+c-6=0 (c+3)(c-2)=0 c=-3 c=2 2^x=-3 this is impossible 2^x=2 x=1
all x are 2,1/2,1 sum=7/2
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so 7/2?
THAnk you SOo much I understand it
yes 7/2 x=2,1,1/2 nop
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