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4tanx=sqrt(3)*sec^2x
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Recall your identity:\[\Large\color{#CC0033 }{\sec^2x\quad=\quad \tan^2x+1}\]
\[\Large 4tan x=\sqrt3\;\color{#CC0033 }{\sec^2x}\]\[\Large 4\tan x=\sqrt3\;(\color{#CC0033 }{\tan^2x+1})\] So there is our first step, mmk?
Or if that's confusing maybe we could just divide the tangent over or something.
where ya at nev?
Sacramento
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