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OpenStudy (anonymous):
WHAT IS THE EXCLUDED VALUE FOR x-8/x^2-2x+1 please last one , someone?
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OpenStudy (anonymous):
\[\frac{ x-8 }{ x^{2} - 2x +1 }\] Find what value of x will make the denominator equal to zero, since division by zero is impossible. \[x^{2} - 2x + 1 \rightarrow (x-1)(x-1)\] If you plug in 1, you will get 0 for the denominator. So the excluded value is 1.
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