Question

WHAT IS THE EXCLUDED VALUE FOR x-8/x^2-2x+1 please last one , someone?

Answer 1

\[\frac{ x-8 }{ x^{2} - 2x +1 }\]
Find what value of x will make the denominator equal to zero, since division by zero is impossible.

\[x^{2} - 2x + 1 \rightarrow (x-1)(x-1)\]

If you plug in 1, you will get 0 for the denominator. So the excluded value is 1.