Question

4x^3-8x = 0
solve for x

Answer 1

4x(x^2-2)=0
4x=0 x=0 or x^2-2=0 x^2=2 x=+(2^1/2) or x=-(2^1/2)

Answer 2

4x^3-8X=0
X(4X^2-8)=0
4X^2-8=0 DIVIDED BY X
4X^2-8=0
4(X^2-2)=0
X^2-2=0 DIVIDED BY 4
X^2-2=0
X^2=2
X=SQUARE ROOT OF 2