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solve cos x tan x - sin^2 x=0 for all real values of x??
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\[ \cancel{\cos x} \frac{\sin x}{\cancel \cos x} - \sin^2 x=0=>\sin x(1-\sin x)=0\] \[\sin x=0 ||\sin x=1\] \[x=0 || x= \frac{\pi}{2}\]
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