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Graph each function. Label the axis of symmetry and the vertex.
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\[y=x ^{2}-4\]
vertex (0,)-4
(0,-4) = vertex aos=0
Thank you
could you help with a few more?
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welcome :) sure
y=-1/2x^2 + 4x + 1
am i adding those?
y=1/2x^2 + 2x -3
What do you mean?
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oh nvmd lol sorry yu want me to fin vertex and aos right?
Yes please
1st one v=(4,9) aos=4
2nd one v=(2,-1) aos=2
Thank you!
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welcome :)
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