Question

how would I find dy/dx in y=4^x *ln??

Answer 1

@shamil98

Answer 2

4^x*what?

Answer 3

4^x times ln

Answer 4

\[\begin{array}{rcl}
y&=&4^x\\
\ln y&=&\ln4^x\\
\ln y&=&x\ln4\\
\frac d{dx}\ln y&=&\frac d{dx}x\ln4\\
\frac1y\cdot\frac{dy}{dx}&=&\ln4\\
\frac{dy}{dx}&=&\ln4\cdot4^x
\end{array}\]
Now use product rule :)

Answer 5

Ln what?

Answer 6

You can't multiply by ln. That doesn't really mean anything

Answer 7

that's what it says....

Answer 8

ln of what? ln(x)?