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How do I check if this solution is extraneous? Please help. sqrt{2x+6}-sqrt{x-1}=2
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\[\sqrt{2x+6}-\sqrt{x-1}=2\]
Since it's the second time you ask this kind of questions, I'm gonna send you a video to help you: http://www.youtube.com/watch?v=711pdW8TbbY
Have you tried solving it? :)
OS values the learning process rather than the answer. Please work out the solution by yourself and we will guide you.
Is \(2x+6 \ge 0\)? Is \(x-1 \ge 0\)?
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