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(____)^2=(secx-1)(secx+1)
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what does this also equal
$$y^2 = (\sec x - 1)(\sec x + 1) = \sec^2 x - 1 = \tan^2 x$$
so tanx is the answer?
no
hmm...
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??? why no???
im pretty sure it is tanx
I am with you, OK, if you fail, me too. You are not alone, hehehehe
haha great
Please, be aware of the fact that your credit is real while mine is fake. hehehhe
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