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help ?!?!?! Jim is designing a seesaw for a children's park. The seesaw should make an angle of 45° with the ground and the maximum height to which it should rise is 1 meter, as shown below.
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What is the maximum length of the seesaw? 1 meter 1.4 meters 2 meters 0.5 meters
sqrt(2). about 1.4
sin(45) = opposite / hypotenuse = 1 / x where x is the length of the see-saw. Solve for x.
|dw:1387665728975:dw| righ??
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