Question

How do I divide and simplify if possible?

Answer 1

waiting on the problem.

Answer 2

\[\frac{ \sqrt{250x ^{16}} }{ \sqrt{2x}? }\]

Answer 3

darn ignore the ? mark

Answer 4

huge \[\huge \frac{ \sqrt{25 * 10 *x^{16} } }{\sqrt{2x}} = \frac{ 5x^4\sqrt{10x^4} }{ \sqrt{2x} }\]

then you multiply the top and bottom by the radical in the denominator.
\[\huge \frac{ 5x^4\sqrt{10x^4} }{ \sqrt{2x} } * \frac{ \sqrt{2x} }{ \sqrt{2x} }\]

\[\huge \frac{ 5x^4\sqrt{20x^5} }{ 2x }\]
\[\huge \frac{ 5x^3 \sqrt{5*4*x^5} }{ 2 } = \frac{ 10x^3\sqrt{5x^5} }{ 2 }\]
\[\huge 5x^3\sqrt{5x^5}\]

Answer 5

I made a huge mistake ugh

Answer 6

√x^16 = x^8

Answer 7

\[\huge \frac{ 5x^8\sqrt{10} }{\sqrt{2x} }\]

Answer 8

\[\huge \frac{ 5x^8 \sqrt{20x} }{ 2x } = \frac{ 10x^7\sqrt {5x} }{ 2 }\]

Answer 9

\[\huge = 5x^7 \sqrt{5x}\]