Question

c program
a bycicle has 4bit lock which can be opened only if there are at least 2 ones in the code. write a program to enter decimal code and verify it can open the lock

Answer 1

Just check each digit? If number of ones >= 2, it opens it. What else?

Answer 2

need code

Answer 3

I don't know C but I know java, so here's basically the pseudocode:

make an integer called count whose value is 0;
for (n from 1 to 4)
if(the nth digit of the string is 1)
add one to count;
if (count>=2)
say yes;

Here's the actual java code:
int count = 0;
for (int n=0; n<4; n++)
if(str.charAt(n)==1)
count++;
if (count>=2)
return true;

I don't know java but I think that java and c are similar so you can just convert it :)

Answer 4

Here come the Java people.
@kc_kennylau Nice try though.

Answer 5

xD

Answer 6

thnx for help :-)

Answer 7

no problem :)