Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

Find the number of permutations in the word “freezer”

OpenStudy (raden):

freezer ----> there are 7 letters r = 2 times e = 3 times so, number permutations = 7!/(2!3!) = 7.6.5.4.3.2.1/(2.1.3.2.1) = ...

OpenStudy (anonymous):

Raden is right!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!