The area of a square is found by squaring one of its sides, (A = s 2). A certain square has an area of z 2 + 18z + 81. Factor the trinomial to find a side of the square.

side = z + 27
side = z + 18
side = z + 9

Question

The area of a square is found by squaring one of its sides, (A = s 2). A certain square has an area of z 2 + 18z + 81. Factor the trinomial to find a side of the square.


side = z + 27
side = z + 18
side = z + 9

kc_kennylau · Answer

Use the identity $\large a^2+2ab+b^2=(a+b)^2$ :)

kc_kennylau · Answer

Use it to factorize $\large z^2+18z+81$ :)

jhonyy9 · Answer

@dirtydan667

dont like you cooperate anything

nurali · Answer

so to factor the trinomal: 
z^2+18z+81

In this problem 9*9=81 and 9+9=18, so insert 9 as the right hand term of one factor and 9 as the right-hand term of the other factor.
(z+9)(z+9)

Combine the two common factors of (z+9) by adding the exponents.
(z+9)^2

nurali · Answer

so since it would factor out to be (z+9)^2 this would be equivalent to (z+9)(z+9)
so, there for side = z + 9