Question

I need some more clarification on this.

Answer 1

how much time? lol

Answer 2

No, time's up!

Answer 3

yeah too long.... too long...

Answer 4

\[\huge\color{blue}{ \lim_{x \rightarrow 3}~~\frac{x^2-9}{x-3} } \]
is plugging 3 for x called a Hospital's rule?

Answer 5

Nope. You'd need to take a derivative of the top and bottom and compare the ratio to be L'Hopital's rule.

Answer 6

you wanto knw what L hospital rule is,

or you wanto evaluate the limit ?

Answer 7

for some reason I have the strange feeling that we aren't talking about medical stuff or Hostpitals

Answer 8

lol thats funny ;)

Answer 9

Well, lets start from this.

When I plug in 3 for x what is this called?

Answer 10

So L'H's rule is if f(x)/g(x) is an indeterminate form like 0/0 or infinity/infinity then,

lim f(x)/g(x) = lim f'(x)/g'(x)

Not the same as quotient rule at all, be careful. Don't confuse the two.

Answer 11

Oh, so plugging it in is quotient rule.

Answer 12

its called 'taking the limit' or 'plugging the x value'

but u cannot plug in 3 here, not yet. cuz that wud give u 0 in the bottom

Answer 13

That's just called trying to solve the limit I think, not the quotient rule.

Answer 14

But when you do, you get an indeterminate form, so then you can invoke L'H's rule.

Answer 15

So I would take \[\huge\color{red}{ \lim_{x \rightarrow 3}~~~\frac{2x}{1} = \frac{2(3)}{1}=6} \]
I am using 2x/1 instead of the original thing, correct?