Question

HELPPPPP!!!!!!!!!!! find the 8th term: (2x-4)^13

Answer 1

By the binomial theorem,
\[(2x-4)^{13}=\sum_{k=0}^{13}\dbinom{13}k (2x)^{13-k}(-4)^{k}\]
The 8th term occurs when \(k=7\), which would be
\[\binom{13}7 (2x)^6(-4)^7\]

Answer 2

huh????? haha none of that made sense....