Question

write an equation in standard form of a parabola with zero's of -2 and 5, passing through (1,8)

Answer 1

so you know it will sort of look like this
(x-5)(x+2)
notice if i put in -2, or 5 we get 0
now we take care of the point (1,8)
so
a(x-5)(x+2) is going to be our form
so
a(1-5)(1+2) = 8
a(-4)(3) = 8
a(-12)=8
a = -2/3
so
our equation is
\[\frac{-2}{3}(x-5)(x+2)\]

Answer 2

thanks :)

Answer 3

np