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Mathematics 21 Online
OpenStudy (anonymous):

1/3x(x+9y)-2

OpenStudy (anonymous):

Multiply, use the distributive property

OpenStudy (shamil98):

Use it then. What do you get?

OpenStudy (anonymous):

1/3x^2+3xy-2/3? im not really sure

OpenStudy (shamil98):

\[\frac{ 1 }{ 3 }x (x+9y) - 2\] \[\frac{ x^2 }{ 3 }+3xy - 2\]

OpenStudy (shamil98):

You are multiply the 1/3 x into what is inside the parentheses only

OpenStudy (shamil98):

a × (b + c) = a × b + a × c

OpenStudy (anonymous):

so everything was right except the last part where I multiplied 1/3x by 2

OpenStudy (shamil98):

yeah

OpenStudy (anonymous):

oh ok thank you

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