Question

i have written this program in c language to change any non-letter characters int an asteric '*' >> it do not gives me any compiling error but that what happens when i debug it
here you are the code first :
int main(){int i=0;
char s1[50],s2[50];
printf("please enter the phrase");
gets(s1);
while (s1[i]!='\0')
{if (s1[i]>='a'&&s1[i]<='z')
{ s2[i]=s1[i];}
else
{s2[i]='*';}
i++;}
puts(s2);

Answer 1

and here the the task window

Answer 2

it does change the character but what are those missed up letters in the middle what is the error ?

Answer 3

you might want to have the output of s2 in array

Answer 4

here is the code in c++, it is similar to c, but it should work

Answer 5

#include <iostream>

using namespace std;

void main(){
int i =0,c; char s1 [50];
cout <<"how many character ";
cin>>c;
cout <<"Please Enter the Phrase ";cin>>s1;
for (i = 0; i<c; i++){
{
if (s1[i]>='a'&&s1[i]<='z'){
cout<<s1[i];}
else
{
s1[i]= '*';
cout <<s1[i];
}

}
}
cout<<endl;

}

Answer 6

The problem is you never end the string `s2` with a null terminator, and so the program does not think the sting has ended yet and continues to print out whatever is in memory until it reaches `'\0'` (which is the `char` equivalent to the `int` value `0`).

Consider putting `s2[i]='\0';` after the loop finishes and before printing `s2`.