Question

What is the center of a circle with this equation: (x+4)^2 + (y-8)^2 = 81?

Answer 1

The center is (h,k)
(x-h)^2 + (y-k)^2 = r^2

(-4,8)
are your values
because (x-(-4)^2 + (y-+8)^2 = 9^2
becomes (x+4)^2 + (y-8)^2 = 81

Answer 2

Thank you VERY much!