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using Euclidean algorithm find GCD(1071,462)
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1071 = 462*2+147 462 = 147*3+21 147 = 21*7+0 so the answer is 21
\[\begin{array}{rcl} 1071&=&2\times\color{blue}{462}&+&\color{green}{147}\\ \color{blue}{462}&=&3\times\color{green}{147}&+&\color{red}{21}\\ \color{green}{147}&=&7\times\color{red}{21}&+&0 \end{array}\]Therefore GCD(1071,462) is 21
so you do that process until you get 0 as a remainder then the answer is the last remainder you were given
very pretty
and now you can find the LCM very easy as well:)
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@sherahhhh what do you not understand? :)
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