Question

which of the following is a polynomial with roots -sqrt5 ,sqrt5^-3?
x^3-2x^2-3x+6
x^3+3x^2-5x-15
x^3-3x^2-5x+15
x^3+2x^2-3x-6

Answer 1

i think its c

Answer 2

i don't think i did polynomial yet let me find out how to do it...

Answer 3

oh ok

Answer 4

\[-\sqrt{5}~~~~~~~~~~and~~~~~~~~\sqrt[5]{-3}?\]

Answer 5

oi oi oi...im sorry this is not something i can learn in 10 minutes...

Answer 6

nope its \[-\sqrt{5} \sqrt{5} -3\]

Answer 7

@SolomonZelman

Answer 8

\[\sqrt{5},~~~~-\sqrt{5}~~~~~~and~~~-3~~?\]

Answer 9

yes

Answer 10

Set each equal zero, and factor, this is way to get it.

Answer 11

so im wrong??

Answer 12

I don;t know, I'll check.

Answer 13

i got c. but if im wrong ill do it aggain

Answer 14

x^3-3x^2-5x+15=0
x^2(x-3)-5(x-5)=0
(x^2-5)(x-3)=0
x^2-5=0 +-sqrt5
x-3=0 3

Answer 15

close, everything beside -3.

Answer 16

Option B.
x^3+3x^2-5x-15=0
x^2(x+3)-5(x+3)=0
(x^2-5)(x+3)=0

B is it, see why?

Answer 17

yea i do.
can u help me with 2 more? there easy

Answer 18

I can try, I'm not very good ta math...go!

Answer 19

which polynomial identity will prove that 37=64-27?
difference squares
difference of cubes
sum of cubes
square of a binomial

Answer 20

What what?! Honestly your teacher is not feeling well, or whatever it is.... Idk, I never had to prove such an obvious statement.

Answer 21

lol

Answer 22

is it d?

Answer 23

I honestly don;t know I would tell you if I did.

Answer 24

oh ok thnk

Answer 25

Yeah sorry abt that.

Answer 26

I can help with something else or at least try to.