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2 tan(4x) / 1 - tan (4x) tan (4x) is equal to: a) tan 2 x b) tan 4 x c) tan 8 x d) tan x
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you need this formula : tan(a+b) = (tan(a) + tan(b))/(1-tan(a)(tan(b))
or even this would work directly :P tan 2A = 2 tan A/ (1+ tan^2 A)
correction it is \[\tan 2A=\frac{ 2\tan A }{1-\tan ^{2}A }\]
just typo from hartnn :P
I know only typing error.
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thanks for correcting :)
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