simplify completely 3x^2+21x-54/x^2+3x-54
\[\huge\color{blue}{ \frac{3x^2+21x-54}{x^2+3x-54 } } \] \[\huge\color{blue}{ \frac{3(x^2+7x-18)}{x^2+3x-54 } } \] \[\huge\color{blue}{ \frac{3( x+9 ) (x-2)}{(x-6)(x+9) } } \]
Go from here.
was gonna say let her factor it out, she's asked previous questions with the same thing, ...
Oh, I didn't see the previous question, just logged on, sorry.
@helpineedit, can you do it from where I left of?
\[\huge\color{blue}{ \frac{3 \color{red} { (x+9) } (x-2)}{(x-6)\color{red} { (x+9) } } } \]see what cancels?
so 3(x-2)/(x-6)
Yup!
thnks for helping me :)
YW!
could u help me with 3 more?
i can try at least.
Ask
simplify completely 2x^2+13x+20/x^2-5x-36
\[\huge\color{blue}{ \frac{2x^2+13x+20}{x^2-5x-36 } } \]can you do this the same way I did the previous question?
2+13x+20/-5x-36
What? Are you saying that that's the question (instead of what I wrote) ?
oh no i was trying and i guess failing at canceling out
Sorry, hold on.
Factor the numerator and denominator..
\[\huge\color{red}{ \frac{2x^2+13x+20}{x^2-5x-36} } \] \[\huge\color{blue}{ \frac{ (2x~+~\text{_})(x~+~\text{_}) }{ (x~-~~\text{_})(x~+~\text{_})} }\]
Fill in blanks.
(2x+13x)(x+20) (x-5x)(x+36)
Wow, no, you are incorrect.
darn! it was kind of confusing what number to put were sorry
Lets try to think. For the top 2a+b=13 a*b=20 For the bottom a-b=5 a*b=36
(a and b are the 2 constants)
ok i tried to do the problem and this is what i got 2(x+10)/x-9
No.
Can you factor it out? (Again) For the top 2a+b=13 a*b=20 For the bottom a-b=5 a*b=36
ohh yea your right.
is there a 13 in it at all?
What do you mean?
like im not sure if its 13x+5 or 2(13x+5)
Do you know how to factor at all? To me you seem unprepared for this, do you want to learn how to factor?
yes please
Or I can make a question where you would get an IS tutor, I am not good at teaching from zero, sorry.
its ok i have to leave in a bit and need this done so maybe i can find another way
Alright.
Join our real-time social learning platform and learn together with your friends!