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what is the restriction on the quotient of 5x^2-10x-15/x^2=9 divided buy 6x+12/x+2
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i think you wrote x^2-9
i meant x+2 in the end part
x cant be -4
please repeat your statement once more.
5x^2-10x-15/x^2-9 divided buy 6x+12/x+2
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\[\frac{ 5x ^{2}-10x-15 }{ x ^{2}-9 }\times \frac{ x+2 }{ 6x+12 }\] now you can solve. Find the values for denominator is 0.
-3? @surjithayer
x^2-9=(x+3)(x-3)
does that mean its positive instead?
@surjithayer
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3,-3,-2
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