Question

What is the standard form of the equation of a circle that has its center at (-2, -3) and passes through the point (-2, 0)?
a) (x + 2)2 + (y + 3)2 = 9
b) (x − 2)2 + (y − 3)2 = 16
c) (x − 2)2 + (y − 3)2 = 4
d) (x + 2)2 + (y + 3)2 = 16
e) (x − 2)2 + (y + 3)2 = 9

please help !

Answer 1

(x-a)^2+(y-b)^2 = r^2
is the equation of a circle with center (a,b) and radius r

Answer 2

what is the radius?
hint: the distance between two points (a,b) (c,d) is given by
\[\sqrt{(a-c)^2+(b-d)^2}\]

Answer 3

are you there @tracynicolexoxo

Answer 4

yeah im here sorry lol

Answer 5

do you understand?

Answer 6

not really im horrible at math