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Mathematics 9 Online
OpenStudy (anonymous):

how to solve this ?! 2^x+1=1/16

OpenStudy (anonymous):

2^(x+1)

OpenStudy (anonymous):

no it is like this

OpenStudy (anonymous):

(x+1)=-4

OpenStudy (kc_kennylau):

\[\Huge\begin{array}{rcl}2^{x+1}&=&\frac1{16}\\2^{x+1}&=&2^{-4}\\x+1&=&-4\\x&=&-5\end{array}\]

OpenStudy (anonymous):

OK thanks @kc_kennylau

OpenStudy (kc_kennylau):

@boyb39 please put parentheses -_-

OpenStudy (kc_kennylau):

no problem

OpenStudy (anonymous):

ok next time

OpenStudy (kc_kennylau):

ok :)

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