Question

i need help finding the zeros of this equation help please? x3 – x2 + 5x – 5 = 0

Answer 1

3x2-5x-2=0


Find the factors such that the product of the factors is the trinomial 3x2-5x-2. This can be done by trial and error and checked using the FOIL method of simplifying polynomials.

(3x+1)(x-2)=0


Set each of the factors of the left-hand side of the equation equal to 0.

3x+1=0


Set each of the factors of the left-hand side of the equation equal to 0.

x-2=0


Since 1 does not contain the variable to solve for, move it to the right-hand side of the equation by subtracting 1 from both sides.

3x=-1


Divide each term in the equation by 3.

3x/3=-1/3


Simplify the left-hand side of the equation by canceling the common terms.

x=-1/3


Since -2 does not contain the variable to solve for, move it to the right-hand side of the equation by adding 2 to both sides.

x=2


The complete solution is the set of the individual solutions.

Answer 2

the equation is x^3 – x^2 + 5x – 5 = 0

Answer 3

x3 – x2 + 5x – 5 = 0
group-
(x3 – x2 )+ (5x – 5) = 0
factor
x2(x-1)+5 (x-1)
factor again
(x-1)(x2+5)

set both to zero
(x-1)=0
(x2+5)=0
and solve for x
(x2+5)=0

Answer 4

Question closed thanks guys! Thanks to venessa for bets response!

Answer 5

i mean vanessa was answer the wrong question :)

Answer 6

oh well

i thought you wanted a start to the question you asked.
i will try and be more intutive!!!
next time!