Question

Differentiate:
\[\LARGE y=sin(5x)\]

Answer 1

use chain rule or just 5.cos 5x

Answer 2

I would use chain rule right?
\[\LARGE y'=(sin(5x)'(5x)'\]
Which gives me:
\[\LARGE y'=5cos5x\]

Answer 3

y = sin(5x)
Let u=5x
du/dx = 5

y = sin(u)
dy/du = cos(u) = cos(5x)

dy/dx = (dy/du)(du/dx)
= cos(5x) * 5
= 5cos(5x)