Question

x+4
--------
x2−5x+6
÷
x2−16
-------
x+3

Answer 1

When dividing fractions, you have to switch the sign and flip the second equation: \[\LARGE \frac{x+4}{x^2-5x+6}*\frac{x+3}{x^2-16}\]
Now just factor.

Answer 2

\[\frac{ x+4 }{ x^2-5x+6 }*\frac{ x+3 }{ x^2-16 }\]

\[\frac{ x+4 }{ (x-2)(x-3) }*\frac{ x+3 }{ (x+4)(x-4)}\]

Answer 3

\[\frac{ x+3 }{ (x-2)(x-3)(x-4) }\]

Answer 4

thank you again! @Nurali :)

Answer 5

My Pleasure.