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The graph of which quadratic equation has a vertex of (–2, 1)?
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Do we need to make one up or..?
information not enough
that's why i'm confused i feel like the question doesn't have enough information here are the answers they give y = (x + 1)2 – 2 y = (x – 1)2 – 2 y = (x + 2)2 + 1 y = (x – 2)2 + 1 @Luigi0210 and @Jonask
\[y=a(x-p)^2+q\]vertex (p,q) in normal cases you should have an extra point given however they aready showing u dat a=1
so i just plug it in
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never mind i found out thank you
yes the 3rd one is correct
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