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OpenStudy (anonymous):
what are the zeros of the function f(x)=4x^2-36x/x-9
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undeadknight26 (undeadknight26):
Discontinuous at x = 9 [Hole] Zero is only 0 since: 0 = 4x(x - 9)/(x - 9) 0 = 4x x = 0 found from: http://answers.yahoo.com/question/index?qid=20110716104158AAESyMD
undeadknight26 (undeadknight26):
Did that help?
OpenStudy (anonymous):
I believe you are wrong. But first lets ask helpineedit to clarify the function for us
undeadknight26 (undeadknight26):
oh ok.
OpenStudy (anonymous):
Can you please write down the function again? Using brackets
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undeadknight26 (undeadknight26):
(4x² - 36x)/(x - 9) :D
OpenStudy (anonymous):
yea thats right @undeadknight26
undeadknight26 (undeadknight26):
so that means what i just said is correct.
OpenStudy (anonymous):
Yes, sorry
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