Question

what are the zeros of the function f(x)=4x^2-36x/x-9

Answer 1

Discontinuous at x = 9 [Hole]
Zero is only 0 since:
0 = 4x(x - 9)/(x - 9)
0 = 4x
x = 0
found from:
http://answers.yahoo.com/question/index?qid=20110716104158AAESyMD

Answer 2

Did that help?

Answer 3

I believe you are wrong. But first lets ask helpineedit to clarify the function for us

Answer 4

oh ok.

Answer 5

Can you please write down the function again? Using brackets

Answer 6

(4x² - 36x)/(x - 9) :D

Answer 7

yea thats right @undeadknight26

Answer 8

so that means what i just said is correct.

Answer 9

Yes, sorry