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Choose the equation of the line passing through the point (-1, 7) and perpendicular to y = -negative one fourthx - 5. y = -4x - 11 y = -4x - 3 y = 4x + 11 y = 4x + 3
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y = -negative one fourthx - 5 slope is -1/4=m when perpendicular m' *m=-1 so m'=+4
now write the line with slope +4 and passing through the point (-1, 7)
according to my calculations, the answer is y=4x + 8 i used the slope-point formula
so the slop is 4
y-y0=m'(x-x0) y-7=4(x-(-1)) y-7=4x+4 so y=4x+11
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