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if cos0=-40/41 and sin0=9/41 what is the value of tan0 in quadrant 2
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Let's draw a picture.
would it be -40/9
Not exactly. \[\LARGE tan \theta=\frac{opp}{adj}\]
use this \[1 + \tan ^{2} \theta = \sec ^{2}\theta \] it gives u the most advance answer
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