Question

Help with solving exponential equation please!

Answer 1

\[3^{3x}-5\left(3x\right)=-6\]

Answer 2

graph 3^3X
and graph 15x-6
but it has no answer

Answer 3

But how would you solve it algebraically?

Answer 4

oops sorry it should be 3^2x

Answer 5

\[3^{2x}-5\left(3x\right)=-6\]

Answer 6

now x=1 is a root check it !

Answer 7

are you sure to type it correct !?

Answer 8

3^(2x)−5(3^x)=−6 isn't it ?

Answer 9

if yes assume 3^x=a
so a^2-5a=-6
a^2-5a+6=0
then (a-2)(a-3)=0
a=2
a=3
3^x=3 --->x=1
3^x=2 --->x=log (base 3) 2

Answer 10

thanks! :)