Medals given! Pleease help! Solve for x. -ax + 2b > 8 x < the quantity negative 2 times b plus 8 all over negative a x > the quantity negative 2 times b plus 8 all over negative a x < the quantity 2 times b minus 8 all over negative a x > the quantity negative 2 times b minus 8 all over a
a>0 ? or a<0
These are the answer choices. A.x < the quantity negative 2 times b plus 8 all over negative a B. x > the quantity negative 2 times b plus 8 all over negative a C. x < the quantity 2 times b minus 8 all over negative a D. x > the quantity negative 2 times b minus 8 all over a
-ax + 2b > 8 suppose a<0 then -ax>8-2b -a>0 so divide by -a x>(8-2b)/(-a) for a<0
would the answer be B?
yeah
−ax+2b>8 −ax>−2b+8 −ax>8−2b −ax−1a<8−1a−2b−1a ax1a<8−1a−2b−1a axa<8−1a−2b−1a x<8−1a−2b−1a x<−81a−2b−1a x<−8a−2b−1a x<−8a+2b1a x<−8a+2ba x<2ba−8a
−ax+2b>8 −ax>−2b+8 −ax>8−2b −ax−1a<8−1a−2b−1a ax1a<8−1a−2b−1a axa<8−1a−2b−1a x<8−1a−2b−1a x<−81a−2b−1a x<−8a−2b−1a x<−8a+2b1a x<−8a+2ba x<2ba−8a i got the same answer as some other guy but.... whatever
Should be 2b-8 over a, but I don't know how to do fractions on here, so I say the answer is C
Is the answer C or B?
C
I say C
i got -ax+2b>8 x>8-2b/-a
Below are the steps to solve an equation: Step 1: |x - 2| + 3 = 7 Step 2: |x - 2| = 7 - 3 Step 3: |x - 2| = 4 Which of the following is a correct next step to solve the equation? x + 2 = -4 -x - 2 = 4 x + 2 = 4 x - 2 = -4
Well...
-Thinks give me a sec-
thanks <3
z - 2 = -4... i think
if i helped give me a medal....
These are the answer choices. x + 2 = -4 -x - 2 = 4 x + 2 = 4 x - 2 = -4
its x -2 = -4
anything else?
Choose the correct description of the graph of the compound inequality 2x + 5 > 9 and 5x less than or greater to 30. A number line with an open circle on 2, shading to the left, and a closed circle on 6, shading to the right. A number line with an open circle on 2, a closed circle on 6, and shading in between. A number line with a closed circle on 2, shading to the left, and an open circle on 6, shading to the right. A number line with a closed circle on 2, an open circle on 6, and shading in between.
-Reads- -Hmmmmm-
See attachment
Srry im kinda stomped on this 1....
2x + 5 > 9 2x + 5-5 > 9-5 2x > 4 2x/2 > 4/2 x > 2
So 2x + 5 > 9 turns into x > 2
5x <= 30 5x/5 <= 30/5 x <= 6 ------------- So 5x <= 30 turns into x <= 6
this means 2x + 5 > 9 and 5x less than or greater to 30 is the same as x > 2 and x <= 6
assuming that the "less than or greater to" is actually "less than or equal to"
theres your answer...?
@DatSmartGuy yeah
A number line with an open circle on 2, shading to the left, and a closed circle on 6, shading to the right. A number line with an open circle on 2, a closed circle on 6, and shading in between. A number line with a closed circle on 2, shading to the left, and an open circle on 6, shading to the right. A number line with a closed circle on 2, an open circle on 6, and shading in between. which is the best answer? :3
Where's your answer? @DatSmartGuy
@Trojan i didn't have one....
Ok
@MyChem Did I help you?
you all helped but I'm not sure what the correct answer was for the last question I posted.
Which was...?
Choose the correct description of the graph of the compound inequality 2x + 5 > 9 and 5x less than or greater to 30. A number line with an open circle on 2, shading to the left, and a closed circle on 6, shading to the right. A number line with an open circle on 2, a closed circle on 6, and shading in between. A number line with a closed circle on 2, shading to the left, and an open circle on 6, shading to the right. A number line with a closed circle on 2, an open circle on 6, and shading in between.
Oh...................................
yah i just need the answer so I can turn it in
Well chem the answer is.... Let me just do i'll give it to you....
alrighty
Its a number line with a closed circle on 2, an open circle on 6, and shading in between.
Does this mean I get a medal or fan...?
a medal! ;D
could you help with one more pleasee?
The perimeter of a rectangle is 64 units. Can the length x of the rectangle can be 20 units when its width y is 11 units? No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 64. No, the rectangle cannot have x = 20 and y = 11 because x + y ≠ 32. Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 64. Yes, the rectangle can have x = 20 and y = 11 because x + y is less than 32.
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