Assuming the balls to be identical except for difference in colours, the number of ways in which one or more
balls can be selected from 10 white, 9 green and 7 black balls is?

Question

Assuming the balls to be identical except for difference in colours, the number of ways in which one or more
balls can be selected from 10 white, 9 green and 7 black balls is?

anonymous · Answer

They are asking how many ways in which "one" or more can be selected so you can pretty much get one a different way for each ball. so 10+9+7

anonymous · Answer

Start with the zero or more case. You could pick 0-10 white balls, 0-9 green balls, and 0-7 black balls. That's 11 * 10 * 8 = 880 ways to select 0 or more balls. One of those ways is selecting zero balls, so there are 879 ways to select 1 or more balls.

anonymous · Answer

Welcome to OpenStudy @kiransai ! Here's a link to help you around OpenStudy! http://openstudy.com/study#/updates/52f5a913e4b0512c88e5ef0f