Question

part A: solve A= 9/2(x+23) for x.
Part B: determine the value of x when A= 108.
part C: solve-np-90>30 for n. show your work

Answer 1

\[A=\frac{9}{2}(x+23)\] like that?

Answer 2

yes

Answer 3

1) multiply both sides by the reciprocal if \(\frac{9}{2}\) which is \(\frac{2}{9}\)
when i say "multiply" i just mean write it
\[\frac{2}{9}A=x+23\]

Answer 4

last step is to subtract \(23\) from both sides

Answer 5

how do I subtract from a fraction\[\frac{ 2 }{ 9}\]?