Question

help with logs!! (attached picture of problem)

Answer 1

this problem confuses the Shi* out of me! :O

Answer 2

me too! haha i don't get it

Answer 3

ahh a solution exists! *going back to sleep* *snore*

Answer 4

Answer is C, 1

\[\log_b \frac{ D^2 }{ C^3A } = \log_b D^2 - \log_b C^3 A = 2\log_b D - \log_b C^3 - \log_b A\]
\[= 2\log_b D - 3\log_b C - \log_b A\]
\[= 2.5 - 3.2 -3 = 1\]

Answer 5

thanks!

Answer 6

Check out this picture