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Mathematics 12 Online
OpenStudy (anonymous):

int x^3 dx / 2x-1

OpenStudy (shamil98):

u-sub perhaps?

ganeshie8 (ganeshie8):

divide may be

ganeshie8 (ganeshie8):

x^2/2 + x/4 + 1/8 ---------------- 2x-1 | x^3 x^3 - x^2/2 ----------------- x^2/2 x^2/2 - x/4 -------------------- x/4 x/4 - 1/8 ------------- 1/8

ganeshie8 (ganeshie8):

\(\large \int \frac{x^3 dx }{2x-1} = \int \frac{x^2}{2} + \frac{x}{4} + \frac{1}{8} + \frac{1}{8(2x-1)} dx\)

ganeshie8 (ganeshie8):

should be trivial to take integral now

OpenStudy (anonymous):

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