Question

how do i solve 4e^-2x=17?

Answer 1

4e^-2x=17 or 4e^(-2x)=17?

Answer 2

4e^(-2x)=17

Answer 3

divide both sides by 4 to get \(\Huge e^{-2x}=17/4\)
take the natural log of both sides to get
-2x=ln(17/4)
then solve for x

Answer 4

I'll leave the last step(s) to you :)

Answer 5

thank you!