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Mathematics 22 Online
OpenStudy (anonymous):

From a lot of 10 bulbs, which includes 3 defectives, a sample of 2 bulbs is drawn at random. Find the probability distribution of the number of defective bulbs.

OpenStudy (anonymous):

What does probability distribution mean? Does it mean they want you to find the probability of each of the four possibilities?

OpenStudy (anonymous):

for 3 defective bulbs

OpenStudy (anonymous):

list the possible outcomes of the draw then find the probability of each of those outcomes

OpenStudy (anonymous):

probability distribution> none of them being defective= [7C{c is for the combination nCr being=n!/(n-r)!*r!}}2]/10C2 similarly one of them being defective [7C1*3C1]/2C10 and both of them being defective 3C2/10C2

OpenStudy (anonymous):

if you have trouble in the above read about finding probability of happenings using combinations

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