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From a lot of 10 bulbs, which includes 3 defectives, a sample of 2 bulbs is drawn at random. Find the probability distribution of the number of defective bulbs.
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What does probability distribution mean? Does it mean they want you to find the probability of each of the four possibilities?
for 3 defective bulbs
list the possible outcomes of the draw then find the probability of each of those outcomes
probability distribution> none of them being defective= [7C{c is for the combination nCr being=n!/(n-r)!*r!}}2]/10C2 similarly one of them being defective [7C1*3C1]/2C10 and both of them being defective 3C2/10C2
if you have trouble in the above read about finding probability of happenings using combinations
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