Question

I have questions on my Semester Review packet I want to make sure what I have already did is correct. I have an attachment below.

Answer 1

1.A
2.C
3B
4C
5R
6A
7B
8C
9 (5,infinity) and (2,infinity)
10 idk
11D
12D
13 -31

Answer 2

1. 4x - 1 = -2(1 - 2x)
4x - 1 = -2 + 4x
4x - 4x = -2 + 1
0 = -1 (incorrect)
answer is D. No solution

2. 2(x - 3) < 5x - 6
2x - 6 < 5x - 6
2x - 5x < -6 + 6
-3x < 0
x < 0
answer is B

3. -3 + 4(x - 1) > 10x + 5 4x + 5(x + 4) > 2x + 48
-3 + 4x - 4 > 10x + 5 4x + 5x + 20 > 2x + 48
4x - 7 > 10x + 5 9x + 20 > 2x + 48
-5 - 7 > 10x - 4x 9x - 2x > 48 - 20
- 12 > 6x 7x > 28
- 2 > x x > 4
answer is B

4. 2 | x - 5 | + 1 >= 3

2(x - 5) + 1 >= 3 -2(x - 5) + 1 >= 3
2x - 10 + 1 >= 3 -2x + 10 + 1 >= 3
2x - 9 >= 3 -2x + 11 >= 3
2x >= 3 + 9 -2x >= 3 - 11
2x >= 12 -2x >= - 8
x >= 6 x <= 4
answer is C

5. | 4x + 5 | = 9

4x + 5 = 9 -4x + 5 = 9
4x = 9 - 5 -4x = 9 - 5
4x = 4 -4x = 4
x = 1 x = -1
answer is t

6. | 5x - 4 | >= 6

5x - 4 >= 6 5x - 4 <= -6
5x >= 6 + 4 5x <= -6 + 4
5x >= 10 5x <= -2
5x >= 2 x <= - 2/5
answer is D

7. | 8x - 1 | <= 2x + 11

8x - 1 <= 2x + 11
8x - 2x <= 11 + 1
6x <= 12
x <= 2
sorry..I am not sure about this one

8. -3 + 4(x - 1) > x + 5 4x + 5(x + 4) > x + 44
-3 + 4x - 4 > x + 5 4x + 5x + 20 > x + 44
4x - 7 > x + 5 9x + 20 > x + 44
4x - x > 5 + 7 9x - x > 44 - 20
3x > 12 8x > 24
x > 4 x > 3
not sure about the answer to this one

sorry this is all I can check for you now...I will be back on later