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In right triangle ABC , m
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|dw:1388442027606:dw|
solve for y and consider what kind of the triangle is.
keep in mind that the sum of all internal angles in a triangle add up to 180 degrees, thus \(\large \begin{array}{cccllll} A&B&C\\ \uparrow&\uparrow&\uparrow\\ 90^o&+(y+10)^o&+(3y-10)^o=180^o \end{array}\) as @Loser66 said, solve for "y" to find the angles of B and C
y+10 + 3y-10 + 90 = 180 Solve for y
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