If the function is not differentiable at the given value of x, tell whether the problem is a corner, cusp, vertical tangent, or a discontinuity.

y=8/(x+2) at x=-2

Question

If the function is not differentiable at the given value of x, tell whether the problem is a corner, cusp, vertical tangent, or a discontinuity.

y=8/(x+2) at x=-2

anonymous · Answer

First find the value of the function at x = -2.
Plugging in -2, we find that the function does not exist at x= -2. 8/0 is undefined.
A corner, cusp, and a vertical tangent, all imply that the function is continous and exists at that point. However since there is value for x= -2, It is a discontinuity,