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OpenStudy (anonymous):
Please help i will give medal I BEG OF U HELP!
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OpenStudy (anonymous):
Which is an equation of the given line in standard form?
A.
–11x + 6y = –13
B.
–6x +11y = 13
C.
–6x + 11y = –13
D.
–6x + 7y = –17
OpenStudy (jdoe0001):
hmmm is that the correct picture?
OpenStudy (anonymous):
one sec
OpenStudy (anonymous):
OpenStudy (jdoe0001):
\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&(-4\quad ,&-1)\quad &(1\frac{1}{2}\quad ,&2)
\end{array}
\\\quad \\
slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}\implies \cfrac{2-(-1)}{1\frac{1}{2}-(-4)}
\\ \quad \\
y-y_1=m(x-x_1)\implies y-(-1)=m(x-(-4)\\ \quad \\
\textit{in the above, point-slope form, plug in your values and solve for "y"}
\)
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OpenStudy (anonymous):
b.
OpenStudy (jdoe0001):
is that what you got?
OpenStudy (anonymous):
yes
OpenStudy (jdoe0001):
ok
OpenStudy (anonymous):
i was right? :D
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