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Mathematics 21 Online
OpenStudy (anonymous):

Please help i will give medal I BEG OF U HELP!

OpenStudy (anonymous):

Which is an equation of the given line in standard form? A. –11x + 6y = –13 B. –6x +11y = 13 C. –6x + 11y = –13 D. –6x + 7y = –17

OpenStudy (jdoe0001):

hmmm is that the correct picture?

OpenStudy (anonymous):

one sec

OpenStudy (anonymous):

OpenStudy (jdoe0001):

\(\bf \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ &(-4\quad ,&-1)\quad &(1\frac{1}{2}\quad ,&2) \end{array} \\\quad \\ slope = m= \cfrac{rise}{run} \implies \cfrac{y_2-y_1}{x_2-x_1}\implies \cfrac{2-(-1)}{1\frac{1}{2}-(-4)} \\ \quad \\ y-y_1=m(x-x_1)\implies y-(-1)=m(x-(-4)\\ \quad \\ \textit{in the above, point-slope form, plug in your values and solve for "y"} \)

OpenStudy (anonymous):

b.

OpenStudy (jdoe0001):

is that what you got?

OpenStudy (anonymous):

yes

OpenStudy (jdoe0001):

ok

OpenStudy (anonymous):

i was right? :D

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